Physics High School
Answers
Answer 1
The enclosed charge by the box is approximately 12.03 x 10⁻⁹ C.
To find the charge enclosed by the cubical box, we'll use Gauss's law. Gauss's law states that the total electric flux Φ through a closed surface is equal to the enclosed charge (Q) divided by the permittivity of free space (ε₀). The formula is:
Φ = Q / ε₀
Given the total electric flux (Φ) is 1.36 x 10³ N·m²/C, and the permittivity of free space (ε₀) is approximately 8.85 x 10⁻¹² C²/N·m². Now, we'll solve for the enclosed charge (Q).
Step 1: Rearrange the formula to solve for Q:
Q = Φ × ε₀
Step 2: Plug in the given values:
Q = (1.36 x 10³ N·m²/C) × (8.85 x 10⁻¹² C²/N·m²)
Step 3: Perform the multiplication:
Q ≈ 1.36 x 10³ x 8.85 x 10⁻¹²
Q ≈ 12.03 x 10⁻⁹ C
The enclosed charge by the box is approximately 12.03 x 10⁻⁹ C.
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Related Questions
what does the cop of a refrigerator represent? multiple choice question. heat input heat output cooling capacity effectiveness
Answers
The COP (Coefficient of Performance) of a refrigerator represents its effectiveness in converting input electrical energy into cooling capacity. Higher COP values indicate a more efficient refrigerator.
The COP of a refrigerator represents its effectiveness. The usable heating or cooling delivered to work (energy) required ratio, also known as the coefficient of performance, or COP, of a heat pump, refrigerator, or air conditioning system. Higher efficiency, less energy (power) usage, and thus reduced operational costs are all related to higher COPs.
Since heat pumps pump additional heat from a heat source to where the heat is needed instead of just converting effort to heat (which, if 100% efficient, would have a COP of 1), the COP typically exceeds 1. A COP of 2.3 to 3.5 is typical for air conditioners. Since moving heat requires less effort than converting it into heat, heat pumps, air conditioners, and refrigeration devices can have a coefficient of performance.
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Two fixed electric dipoles of dipole moment p are located in the x−y plane a distance 2aapart, their axes parallel and perpendicular to the plane, but their moments directed oppositely. The dipoles rotate with constant angular speed \omega about a z axis located halfway between them. The motion is nonrelativistic (\omegaalc ≪1)≪1).
(a) Find the lowest nonvanishing multipole moments.
Answers
The lowest nonvanishing multipole moments are M1 and N2, which correspond to the dipole and quadrupole moments, respectively.
The lowest nonvanishing multipole moments can be found by expanding the potential due to the two fixed electric dipoles in terms of multipole moments. Since the dipoles are located in the x−y plane and their axes are parallel and perpendicular to the plane, we can use cylindrical coordinates with the z axis as the axis of symmetry.
The potential due to one of the dipoles at position r can be written as:
V(r) = (p/4πε₀) (cos θ/r² - 3cos θz²/r⁴)
where θ is the polar angle and ε₀ is the electric constant. The potential due to the other dipole can be obtained by changing the sign of p. The total potential due to both dipoles is then:
V(r) = (p/4πε₀) [(cos θ/r² - 3cos θz²/r⁴) - (cos θ/r² + 3cos θz²/r⁴)] = (-6pz²/4πε₀r⁴)
To expand this potential in terms of multipole moments, we use the formula:
V(r) = (1/4πε₀) ∑ [((2n+1)/r^(n+1)) (Mn cos nφ + Nn sin nφ) Pn(cos θ)]
where Mn and Nn are the multipole moments, Pn(cos θ) is the Legendre polynomial of degree n, and φ is the azimuthal angle. Since the potential only depends on z and φ, we can set θ=0 and obtain:
V(z,φ) = (-6pz²/4πε₀r⁴) = (1/4πε₀) ∑ [((2n+1)/r^(n+1)) (Mn cos nφ + Nn sin nφ)]
The coefficients Mn and Nn can be found by comparing the two expressions and using the orthogonality of the Legendre polynomials. We obtain:
M1 = -N1 = -6p/√2a³
M2 = N2 = 15√2pa⁵/2
M3 = -N3 = -70√2pa⁷/3
...
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a substance decomposes in a first−order reaction with a rate constant of 6.7 x 10−4 s−1. if the initial concentration of the substance is 1.50 m, what is its concentration after 500. s?
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The concentration of the substance after 500 s is approximately 0.774 M.
In a first-order reaction with a rate constant of 6.7 x 10^(-4) s^(-1) and an initial concentration of 1.50 M, the concentration of the substance after 500 s can be calculated using the first-order decay equation:
Concentration at time t = Initial concentration * e^(-rate constant * time)
Plugging in the given values:
Concentration at 500 s = 1.50 M * e^(-6.7 x 10^(-4) s^(-1) * 500 s)
Concentration at 500 s ≈ 0.774 M
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Parents and teachers should strive to have children engage in activities within the child's zone of proximal growth, meaning that the activities are:
A. easily accomplished on the first try, so that the child does not become discouraged
B. not so easy that the child can accomplish them right off the bat, nor so difficult that even with help, they cannot be accomplished
C. difficult to accomplish, so that the child always seeks assistance in order to actively engage in social interactions
D. easily accomplished, so that child does not become dependent on adult assistance
Answers
Parents and teachers should strive to have children engage in the activities within child's zone of proximal growth, meaning that the activities are : B.)not so easy that the child accomplish them right off the bat and nor so difficult that even with help, they cannot be accomplished.
What are the activities that parents and teachers should strive to have children engage in?
Activities in a child's zone of proximal development are those that parents and teachers should try to get kids involved in. ZPD is the range of activities that are not too easy for the child to accomplish on their own, but also not too difficult that they cannot be accomplished with some guidance or assistance from adults or more capable peers.
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. Obtain an acrylic rod and a piece of wool or fur. Rub the rod with the wool, and then holdthe rod near newly made T and B tapes on the wooden dowel.Compare the interactions of the rod with the tapes to the interactions between the tapes inpart C. Describe any similarities or differences.We say that the rod and tapes are electrically charged when they interact as you haveobserved.
Answers
When you rub the acrylic rod with wool or fur, the rod becomes electrically charged due to the transfer of electrons. When you hold the rod near the newly made T and B tapes on the wooden dowel, you will observe that the tapes are attracted to the rod and may even stick to it. This is because the tapes become polarized due to the electric field of the charged rod, causing opposite charges to attract.
In comparison to the interactions between the tapes in part C, where they were simply held together by their adhesive properties, the interactions between the rod and tapes are due to electric charge. This is a significant difference, as it demonstrates the role of electric charge in attracting and repelling objects.
In summary, the similarities between the interactions of the rod and tapes and the interactions between the tapes in part C are that both involve the tapes being held in place. However, the key difference is that the interactions with the rod involve electric charge, while the interactions in part C do not.
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Why was astronaut ken mattingly replaced by jack swigert on the apollo 13 crew just a few days before launch?
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Astronaut Ken Mattingly was replaced by Jack Swigert on the Apollo 13 crew just a few days before launch due to concerns about his potential exposure to German measles.
Astronaut Ken Mattingly was originally part of the Apollo 13 crew as the Command Module Pilot. However, just a few days before launch, he was replaced by Jack Swigert due to concerns that he might have been exposed to German measles (rubella). One of Mattingly's fellow astronaut's wives had contracted rubella, and Mattingly had never been exposed to the virus before.
As a result, NASA doctors deemed it too risky for him to be on the mission, as the virus could have compromised his immune system and potentially spread to the other crew members. Swigert was chosen as a replacement as he had already been designated as the backup Command Module Pilot.
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Consider two point particles that have charge e, are at rest, and are separated by 1.8 x 1015 m. 1) How much work was required to bring them together from a very large separation distance? 800 You currently have 1 submissions for this question. Only 10 submission are allowed. You can make 9 more submissions for this question. keV Submit Your submissions:800 Computed value: 800 Feedback: Submitted: Thursday, February 21 at 6:54 PM 2) If they are released, how much kinetic energy will each have when they are separated by twice their separation at release? 200 You currently have 5 submissions for this question. Only 10 submission are allowed. You can make 5 more submissions for this question. keV Submit Your submissions: 200 V Computed value: 200 Submitted: Thursday, February 21 at 7:19 PM Feedback: 3) The mass of each particle is 1.00 u (1.00 amu). What speed will each have when they are very far from each other? /s Submit You currently have 6 submissions for this question. Only 10 submission are allowed. You can make 4 more submissions for this question.
Answers
To bring the two particles together from a very large separation distance, we need to calculate the work done. The electrostatic potential energy between the two particles is given by U = (ke x e^2)/r, where ke is the Coulomb constant, e is the charge of each particle, and r is the separation distance.
So, the work done to bring the particles together from infinity to a separation distance of 1.8 x 10^15 m is given by:
W = U(final) - U(initial)
= [(ke x e^2)/(1.8 x 10^15 m)] - 0
= (8.99 x 10^9 Nm^2/C^2 x 1.6 x 10^-19 C^2)/(1.8 x 10^15 m)
= 8.88 x 10^-11 J
When the particles are released and separated by twice their separation at release, the electrostatic potential energy between them is zero. So, the total kinetic energy of the system is equal to the initial potential energy:
KE(total) = U(initial)
= (ke x e^2)/(1.8 x 10^15 m)
Since there are two particles, each will have half of the total kinetic energy:
KE(each) = KE(total)/2
= (ke x e^2)/(2 x 1.8 x 10^15 m)
= 4.44 x 10^-11 J
The kinetic energy can also be expressed in electronvolts (eV) by dividing by the charge of an electron (1.6 x 10^-19 C):
KE(each) = (4.44 x 10^-11 J)/(1.6 x 10^-19 C)
= 277.5 keV
To find the speed of each particle when they are very far from each other, we can use the conservation of energy principle. The initial potential energy is equal to the final kinetic energy:
U(initial) = KE(final)
(ke x e^2)/r = (1/2)mv^2
where m is the mass of each particle and v is their speed.
Solving for v, we get:
v = sqrt[(2 x ke x e^2)/(r x m)]
= sqrt[(2 x 8.99 x 10^9 Nm^2/C^2 x 1.6 x 10^-19 C^2)/(1.8 x 10^15 m x 1.00 u x 1.66 x 10^-27 kg/u)]
= 8.45 x 10^5 m/s
So, each particle will have a speed of 8.45 x 10^5 m/s when they are very far from each other.
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a spherical christmass tree ornament is 6.00 cm in diameter what is the mangiifcation of an object placed 10.0 cm away from the ornament?
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The magnification of an object placed 10.0 cm away from the spherical christmas tree ornament which is 6.00 cm in diameter would be 7.5x.
This is because magnification is the ratio of the size of the image to the size of the object. The distance between the object and the ornament is the focal length of the spherical ornament.
As the focal length is 10 cm, the magnification is equal to the ratio of the diameter to the focal length, which is 6/10 = 0.6. To calculate the magnification, we need to multiply the ratio by the power of the lens, which is 1.25.
Hence, the magnification would be 0.6*1.25 = 0.75, which is 7.5x. Therefore, the magnification of an object placed 10 cm away from the spherical christmas tree ornament would be 7.5x.
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4.24 Saturated liquid R-410a at 25°C is throttled to 400 kPa in a refrigerator. What is the exit temperature? Find the percent increase in the volume-flow rate.
Answers
The percent increase in the volume-flow rate is 9300%
When saturated liquid R-410a at 25°C is throttled to 400 kPa, it undergoes a pressure drop and becomes a mixture of saturated liquid and vapor. To determine the exit temperature, we can use the property tables for R-410a. At 400 kPa, the saturation temperature for R-410a is approximately 4.4°C. Therefore, we can assume that the exit temperature is close to this value.
To find the percent increase in the volume flow rate, we need to use the mass flow rate equation:
m_dot = rho * V_dot
where m_dot is the mass flow rate, rho is the density, and V_dot is the volume-flow rate. Since the refrigerant is throttled, the pressure drop causes an increase in the volume flow rate. The percent increase can be calculated as:
% increase in V_dot = [(V_dot after - V_dot before) / V_dot before] * 100
To calculate the density of the saturated liquid R-410a at 25°C, we can use the property tables again. The density is approximately 1035 kg/m3. Assuming that the volume-flow rate before throttling is 1 m3/min, we can calculate the mass flow rate:
m_dot before = 1035 kg/m3 * 1 m3/min = 1035 kg/min
At the exit condition of 400 kPa and approximately 4.4°C, the density of the refrigerant is approximately 11 kg/m3. Therefore, we can calculate the volume-flow rate after throttling:
V_dot after = m_dot before / rho after = 1035 kg/min / 11 kg/m3 = 94 m3/min
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at what temperature is the change in entropy for the reaction equal to the change in entropy for the surroundings? a reaction has δh∘rxn= -126 kj and δs∘rxn= 318 j/k .
Answers
At a temperature of approximately 396.23 K, the change in entropy for the reaction is equal to the change in entropy for the surroundings.
The temperature at which the change in entropy for the reaction is equal to the change in entropy for the surroundings, you can use the following relation,
ΔStotal = ΔSsystem + ΔSsurroundings
Since ΔSsystem = ΔSsurroundings, the total entropy change (ΔStotal) will be zero. For a spontaneous process, ΔStotal should be greater than or equal to zero. In this case, we have the following relation:
ΔG = ΔH - TΔS = 0
You are given the values of ΔH (ΔH°rxn = -126 kJ) and ΔS (ΔS°rxn = 318 J/K). Convert ΔH°rxn to J to match the units:
ΔH°rxn = -126,000 J
Now, we can use the equation ΔG = ΔH - TΔS = 0:
0 = -126,000 J - T(318 J/K)
Rearrange the equation to solve for the temperature T:
T = -(-126,000 J) / (318 J/K) = 126,000 J / 318 J/K ≈ 396.23 K
So, at a temperature of approximately 396.23 K, the change in entropy for the reaction is equal to the change in entropy for the surroundings.
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find the drift velocity d of conduction electrons in a gold wire of diameter 2.17 mm when a current of 0.313 a flows in it. the density of conduction electrons in gold is 5.90×1028 m−3.
Answers
The drift velocity of conduction electrons in a gold wire with a diameter of 2.17 mm and a density of 5.90×1028 [tex]m^{-3[/tex] carrying a current of 0.313 A is approximately 1.23×[tex]10^_-5[/tex] m/s.
To find the float speed of conduction electrons in a gold wire, we can utilize the equation:
I = nAqvd
Where I is the current, n is the thickness of conduction electrons, An is the cross-sectional region of the wire, q is the charge of an electron, v is the float speed, and d is the breadth of the wire.We can modify the recipe to address for v:
v = I/(nAqd)
Subbing the given qualities, we get:
v = [tex]0.313/(5.90×10^28 × π×(2.17×10^-3)^2/4 × 1.6×10^-19 × 2.17×10^-3)[/tex]
v = 0.0035 m/s
Thus, the float speed of conduction electrons in the gold wire is 0.0035 m/s. This is a somewhat low speed, as conduction electrons commonly move at speeds on the request for micrometers each second in metals because of their continuous crashes with molecules in the grid.
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the rms speed of the atoms in a 2.10 g sample of helium gas is 670 m/s ..What is the thermal energy of the gas?
Answers
The thermal energy of the helium gas is 2.66 x 10^3 J.
To find the thermal energy of the gas, we need to use the formula:
Thermal energy = (3/2) * (number of atoms) * (Boltzmann's constant) * (temperature)
First, we need to find the number of atoms in the 2.10 g sample of helium gas. We can use the atomic mass of helium (4.00 g/mol) and Avogadro's number (6.02 x 10^23) to do this:
Number of atoms = [tex](2.10 g) / (4.00 g/mol) * (6.02 x 10^23 atoms/mol) = 3.15 x 10^22 atoms[/tex]
Now we can plug in the given rms speed of 670 m/s and solve for the temperature using the formula:
rms speed = sqrt((3 * Boltzmann's constant * temperature) / (mass of one atom))
Solving for temperature, we get:
Temperature = (mass of one atom * rms speed^2) / (3 * Boltzmann's constant) =[tex](4.00 x 10^-3 kg/mol * (670 m/s)^2) / (3 * 1.38 x 10^-23 J/K) = 1.62 x 10^4 K[/tex]
Finally, we can plug in all the values we have found into the formula for thermal energy:
Thermal energy =[tex](3/2) * (3.15 x 10^22 atoms) * (1.38 x 10^-23 J/K) * (1.62 x 10^4 K) = 2.66 x 10^3 J[/tex]
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in the circuit, is(t) = 0.2 sin 105t a, r = 20 ω, l = 0.05 mh, and c = 2 μf. the power factor of the source is
Answers
The answer is that the power factor of the source is not defined for the given circuit.
To determine the power factor of the source, we need to first calculate the impedance of the circuit.
The impedance (Z) of the circuit can be calculated using the formula Z = √(r^2 + (ωl - 1/ωc)^2), where r is the resistance, ω is the angular frequency (ω = 2πf, where f is the frequency), l is the inductance, and c is the capacitance.
Plugging in the values given, we get: Z = √(20^2 + (105*0.05*10^-3 - 1/(105*2*10^-6))^2) ≈ 30.02 Ω
Now, the power factor (pf) of the source is given by the formula cos(θ) = Re(P)/|P|, where θ is the phase angle between the voltage and current, P is the complex power, and Re(P) is the real part of the complex power.
Since the current in the circuit is i(t) = 0.2 sin(105t + θ), we can find the phase angle by comparing it to the voltage, which is v(t) = Vm sin(105t).
Taking the ratio of the two, we get: cos(θ) = v(t)/i(t) = Vm/(0.2*Z)
Plugging in the values of Vm = 1 (assuming the voltage is in volts), and Z = 30.02 Ω, we get: cos(θ) = 1/(0.2*30.02) ≈ 1.66
However, this is not possible since the range of cos(θ) is between -1 and 1. This means that the power factor is not defined for this circuit.
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a string that is under 52.0 n of tension has linear density 5.40 g/m. a sinusoidal wave with amplitude 3.40 cm and wavelength 2.10 m travels along the string.
Answers
The speed of the wave can be found using the equation v = √(T/μ), where T is tension and μ is linear density. Plugging in the values given, v = √(52.0 N / 5.40 g/m) = 24.3 m/s.
Therefore, the equation for the wave is
y(x,t) = 3.40 cm sin(2.99 m^-1 x - 73.1 rad/s t).
The general equation for a sinusoidal wave is y(x,t) = A sin(kx - ωt), where A is amplitude, k is wave number (2π/λ), ω is the angular frequency (2πf), and f is the frequency (v/λ).
We know the amplitude (A = 3.40 cm) and wavelength (λ = 2.10 m), so we can find the wave number and frequency:
k = 2π/λ = 2π/2.10 m = 2.99 m^-1
f = v/λ = 24.3 m/s / 2.10 m = 11.6 Hz
Therefore, the equation for the wave is y(x,t) = 3.40 cm sin(2.99 m^-1 x - 73.1 rad/s t).
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an am radio transmitter radiates 500 kw at a frequency of 760 khz. how many photons per second does the emitter emit?
Answers
The AM radio transmitter emits approximately 9.94 x [tex]10^{31}[/tex] photons per second.
To calculate the number of photons emitted per second by an AM radio transmitter, we'll need to use the following terms and equations:
Power (P): This is the amount of energy transferred or converted per unit time. In this case, the transmitter radiates 500 kW (kilowatts).
Frequency (f): The number of cycles of a periodic wave that occur in a unit of time. In this case, the frequency is 760 kHz (kilohertz).
Planck's constant (h): A fundamental constant with a value of approximately 6.626 x [tex]10^{-34}[/tex] Js (joule-seconds). This constant relates the energy of a photon to its frequency.
The energy (E) of a single photon can be calculated using the equation:
E = h x f
Next, we need to convert the power and frequency to the appropriate units:
P = 500 kW x 1,000 (to convert kW to W) = 500,000 W
f = 760 kHz x 1,000 (to convert kHz to Hz) = 760,000 Hz
Now, we can calculate the energy of a single photon:
E = (6.626 x 10^-34 Js) * (760,000 Hz) = 5.035 x [tex]10^{-28}[/tex] J
To find the number of photons emitted per second (n), we will divide the total power (P) by the energy per photon (E):
n = P / E
n = (500,000 W) / (5.035 x [tex]10^{-28}[/tex] J)
n ≈ 9.94 x [tex]10^{31}[/tex] photons per second
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32 An electric motor lifts a mass of 100 kg through a vertical distance of 20 m. Gravitational field strength is 10N/kg. What is the useful work done by the motor? A 5J B 50J C 2000 J D 20000J
Answers
The motor produces 20,000 J of useful work.
What is the process for completing work?
The work W is equal to the force f times the distance d, or W = fd, to represent this idea numerically. Work is defined as W = fd cos if the force is applied at an angle to the displacement. It is considered good to deadlift 100 kg, although it also depends on the person's weight, age, and training background.
Work = Potential energy = mgh
where m is the mass of the object, g is the acceleration due to gravity (gravitational field strength), and h is the height through which the object is lifted.
Substituting the given values:
Work = 100 kg * 10 N/kg * 20 m = 20,000 J
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You are required to use the Chicago Manual of Style for citing sources in your research paper.
What is the proper format for citing the following book in a bibliograbhy?
author: Donald Prezioni
title: Minoan Architectural Design: Formation and Signification
publisher: De Gruyter
date of publication: 1983
source: ProQuest Ebooks
(Not understanding why am I getting it wrong the options attached below)
Answers
Answer:
Prezioni, Donald. 1983. Minoan Architectural Design: Formation and Signification. De Gruter.
Explanation:
A 9.6-V battery is connected in series with a 31-mH inductor, a 190-Ω resistor, and an open switch.
Part A) What is the current in the circuit 0.140 ms after the switch is closed?
I= mA
Part B) How much energy is stored in the inductor at this time?
U= μJ
Answers
A) The current in the circuit 0.140 ms after the switch is closed is 50.5 mA.
B) The energy stored in the inductor at this time is 39.9 μJ.
Part A:
To find the current in the circuit, we can use the equation for the current in an RL circuit:
I = (V/R) * (1 - e^(-t/(L/R)))
where V is the voltage of the battery (9.6 V), R is the resistance (190 Ω), L is the inductance (31 mH), and t is the time (0.140 ms or 0.000140 s).
Plugging in these values, we get:
[tex]I = (9.6/190) * (1 - e^(-0.000140/(0.031/190)))[/tex]
I = 0.0505 A or 50.5 mA
Therefore, the current in the circuit 0.140 ms after the switch is closed is 50.5 mA.
Part B:
To find the energy stored in the inductor, we can use the equation for the energy stored in an inductor:
U = (1/2) * L * I²
where L is the inductance (31 mH) and I is the current (50.5 mA).
Plugging in these values, we get:
[tex]U = (1/2) * 0.031 * 0.0505^{2}[/tex]
U = 39.9 μJ
Therefore, the energy stored in the inductor at this time is 39.9 μJ.
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complex design and construction such as wear, breakdown, and maintenance of mechanical parts are two limitations and shortcomings of mechanical computation?
Answers
The complexity of design and construction of mechanical parts can be a major limitation of mechanical computation.
The wear, breakdown, and maintenance of mechanical parts can cause problems that may be difficult to solve. For example, a machine may need to be taken apart and re-assembled in order to fix problems. This can take a significant amount of time and effort, which may be difficult to justify if the machine is not used frequently.
Additionally, the complexity of the design and construction of mechanical parts can affect the accuracy and reliability of the computation. Due to the complexity of the parts, it can be difficult to ensure that they are all properly aligned and that they are all functioning correctly. This can lead to reduced accuracy and reliability in the computation.
Finally, mechanical parts are subject to wear and tear, which can further reduce the accuracy and reliability of the computation over time. In short, the complexity of design and construction, as well as the wear, breakdown, and maintenance of mechanical parts, can be major limitations and shortcomings of mechanical computation.
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a bass guitar string is 89 cm long with a fundamental fre- quency of 30 hz. what is the wave speed on this string?
Answers
The wave speed on the bass guitar string is 5,340 cm/s.
The wave speed on the bass guitar string can be calculated using the equation v = fλ, where v is the wave speed, f is the frequency, and λ is the wavelength. To find λ, we need to use the formula λ = 2L/n, where L is the length of the string and n is the harmonic number of the fundamental frequency (in this case, n = 1).
So, λ = 2(89 cm)/1 = 178 cm
Now, we can plug in the values for f and λ to find v:
v = (30 hz)(178 cm) = 5,340 cm/s.
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1. Using Wien's Law, what was the peak wavelength of the thermal emission when protons and electrons combined in the early universe, when the temperature was about 3000 Kelvin? 2. Using the color-bar below, what color would this 3000 K thermal radiation appear to human eyes? The color bar shows the color our eyes would see for a range of temperatures from 1000 K to 30,000 K. 1000 2000 4000 8000 16000 32000 (K)
Answers
The peak wavelength of the thermal emission at 3000 Kelvin using Wien's Law is 966 nm. The 3000 K thermal radiation would appear to human eyes as an orange color.
1. To find the peak wavelength of the thermal emission at 3000 Kelvin using Wien's Law, we can use the formula:
Wien's Law: λ_max = b / T
where λ_max is the peak wavelength, b is Wien's constant (2.898 x 10^-3 m*K), and T is the temperature in Kelvin.
For T = 3000 K, we can calculate λ_max as follows:
λ_max = (2.898 x 10^-3 m*K) / 3000 K
λ_max ≈ 9.66 x 10^-7 m, or 966 nm.
2. Based on the color-bar provided, we can estimate the color that corresponds to the 3000 K thermal radiation. The colors in the range of 1000 K to 4000 K are typically in the red-orange area. Since 3000 K is closer to 4000 K, the color would be closer to orange. So, the 3000 K thermal radiation would appear to human eyes as an orange color.
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Levi drove south for two hours. The trip was 160 kilometers long. Halfway there, he looked at his spedometer and saw 40 km per hour. What was his instantaneous speed at that time?
Answers
Levi's instantaneous speed at the moment he looked at his speedometer was 80 km/h, which is consistent with his average speed for the entire trip.
If Levi drove south for two hours and covered a distance of 160 kilometers, then his average speed for the entire trip was:
average speed = total distance / total time = 160 km / 2 h = 80 km/h
Let d(t) be the distance that Levi has driven at time t. Then we have:
d(0) = 0 (starting position)
d(2) = 160 km (final position)
d(1) = 80 km (distance traveled halfway through the trip)
The average speed between time t1 and t2 is given by:
average speed = (d(t2) - d(t1)) / (t2 - t1)
At time t=1, we have:
average speed = (d(2) - d(1)) / (2 - 1) = (160 km - 80 km) / 1 h = 80 km/h
This is consistent with the earlier calculation of the average speed for the entire trip.
The instantaneous speed at time t=1 is given by the derivative of the distance function with respect to time:
instantaneous speed = d'(1)
Using calculus, we can find:
d(t) = 40t^2
d'(t) = 80t
Therefore, the instantaneous speed at time t=1 is:
instantaneous speed = d'(1) = 80 km/h
So Levi's instantaneous speed at the moment he looked at his speedometer was 80 km/h, which is consistent with his average speed for the entire trip.
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If you connect two identical storage batteries together in series ("+" to "-" to "+" to "-"), and place them in a circuit, the combination will provide
the same voltage, and the same current will flow through each.
the same voltage, and different currents will flow through each.
twice the voltage, and the same current will flow through each.
twice the voltage, and different currents will flow through each.
zero volts.
Answers
When two identical batteries are connected in series, their positive terminals are connected to each other, and their negative terminals are also connected to each other. The voltage of the combination is equal to the sum of the voltages of the individual batteries.
The current that flows through each battery is the same, because there is only one path for the current to take. Therefore, the correct answer is that the combination will provide the same voltage, and the same current will flow through each.To understand why this is the case, it is helpful to think about the behavior of the batteries as voltage sources. A voltage source, such as a battery, has a fixed voltage that it will try to maintain, regardless of the current flowing through it. When two identical batteries are connected in series, their voltage sources add up, so the total voltage of the combination is twice that of a single battery. However, since the batteries are identical, they will behave in the same way, and will try to maintain the same voltage across their terminals.
Now, when the batteries are connected in series, the current that flows through the combination will be the same as the current that would flow through a single battery in the circuit. This is because there is only one path for the current to take, and it has to flow through both batteries. Since the batteries are identical, they will have the same internal resistance, and will offer the same amount of opposition to the flow of current. Therefore, the current will split evenly between the two batteries, and will be the same for both.
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A laser beam is is pointed perpendicular to the surface of water in a glass aquarium that is tilted at 30° as shown in the figure above. Ignore any effects of the glass on the beam path. Point P lies directly under the laser as illustrated by the dashed line Where will you observe the laser beam hitting the table? A. To the left of point P B. The beam will not hit the table because it will undergo total internal reflection. C. To the right of Point P D. At point P
Answers
To the right of Point P. So,the correct answer is C.
Where will you observe the laser beam hitting the table?
When a laser beam is pointed perpendicular to the surface of water in a tilted glass aquarium, it enters the water vertically. The light undergoes refraction, which causes it to change direction as it passes from air (less dense medium) into water (denser medium).
According to Snell's Law, the light bends towards the normal as it enters the water, causing the beam to travel through the water at an angle. The glass aquarium is tilted at 30°, which means that the water surface is not parallel to the table.
As the refracted light travels through the water, it eventually reaches the water-air interface at the bottom of the tilted aquarium. When the light exits the water and enters the air, it refracts again. This time, the light bends away from the normal due to the transition from a denser medium (water) to a less dense medium (air).
As a result, the laser beam will hit the table at a point to the right of Point P. The tilted water surface causes the beam to exit the water at an angle and deviate from the original vertical path, making it appear shifted to the right of the original position below the laser.
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Consider a rigid object whose center of mass is at rest. If the net torque on an object is zero, the object O must be at rest could be at rest or could rotate with a constant angular velocity. Question 7 1.42 pts Consider a rigid body that rotates but whose center of mass is at rest. True or false: the rotational kinetic energy of the entire object is equivalent to the sum of the translational kinetic energy of each small piece of the object True False
Answers
If the net torque on a rigid object whose center of mass is at rest is zero, the object could be at rest or could rotate with a constant angular velocity.
For the second question, the statement is false because the rotational kinetic energy of the entire object is not equivalent to the sum of the translational kinetic energy of each small piece of the object.
The rotational kinetic energy of a rigid body that rotates about a fixed axis is given by:
[tex]K_{rot} = (1/2) \times I \times \omega^2[/tex],
where I is the moment of inertia of the body about the axis of rotation, and ω is the angular velocity of the body.
The translational kinetic energy of a small piece of the object is given by:
[tex]K_{trans} = (1/2) \times m \times v^2[/tex],
where m is the mass of the small piece and v is its velocity.
While it is true that the total kinetic energy of the rigid body is the sum of the rotational and translational kinetic energies of all its small pieces, the rotational kinetic energy of the entire object is not equivalent to the sum of the translational kinetic energies of each small piece. These two types of kinetic energies are related, but not interchangeable.
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You toss a chocolate bar to your hiking companion located 8.6 m upa 39 degree slope.
Determine the magnitude of the initial velocity vector so thatthe chocolate bar will reach your friend horizontally.
Determine the direction of the initial velocity vector so thatthe chocolate bar will reach your friend moving horizontally.
Answers
In this case, the magnitude of the initial velocity vector is approximately 10.8 m/s and the direction of the initial velocity vector so that the chocolate bar will reach your friend moving horizontally is downward at an angle of 180 degrees.
How to determine the initial velocity vector
To determine the magnitude of the initial velocity vector, we can use the fact that the chocolate bar needs to travel a horizontal distance of 8.6 m to reach the friend.
We can use the equation for horizontal distance traveled by an object with initial velocity v0 and angle θ: d = v0cos(θ)t
Since the chocolate bar is tossed, we can assume that its initial vertical velocity is zero.
Therefore, we can use the equation for vertical displacement to find the time it takes for the chocolate bar to reach the friend:
y = v0sin(θ)t - 0.5gt²
where y is the vertical displacement (which is 8.6 m in this case) and g is the acceleration due to gravity (-9.81 m/s²).
Solving for t, we get:
t = sqrt(2y/g) = sqrt(2(8.6)/9.81) ≈ 1.26 s
Now we can use the equation for horizontal distance traveled to find the initial velocity:
d = v0cos(θ)t 8.6 = v0cos(39)t
v0 = 8.6/(cos(39)t) ≈ 10.8 m/s
Therefore, the magnitude of the initial velocity vector is approximately 10.8 m/s. To determine the direction of the initial velocity vector, we can use the fact that the chocolate bar needs to travel horizontally.
This means that the vertical component of the initial velocity should be zero.
Therefore, we can use the equation for vertical velocity to find the angle θ:
v0sin(θ) = 0 θ = 0 or 180 degrees
However, we know that the chocolate bar is thrown uphill, so the initial angle cannot be 0 degrees. Therefore, the initial angle must be 180 degrees, which means the initial velocity vector must be directed downward.
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At what moment does the current reverse direction for the first time? View Available Hint(s) 0 0.0 ms 2.0 ms O 4.0 ms O 6.0 ms O 8.0 ms
Answers
At the moment when the current reverses direction for the first time is 4.0 ms. In this context, "current" refers to the flow of electric charge, "reverse" means to change the direction opposite to its initial flow, and "direction" indicates the path along which the current is flowing.
A stream of charged particles, such as electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.
Electrical charge carriers, often electrons or atoms deficient in electrons, travel as current. The capital letter I am a typical way to represent the current. The ampere, denoted by the letter A, is the common unit.
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The space between two metallic coaxial cylinders of length L = 0.450 m and radii a = 1.70 cm and b = 2.70 cm is completely filled with a material having a resistivity = 33.0 m. The figure below shows a cross section of the configuration.
The space between two metallic coaxial cylinders o
a) What is the resistance between the two cylinders? Give your answer with a unit of "Ohm".
b) Find the current between the two cylinders if a potential difference of 19.0 Volts is maintained between the two cylinders.
Please answer both parts and explain how you got the answer.
Answers
The resistance between the two cylinders is 2.13 Ohm. The current between the two cylinders if a potential difference of 19.0 Volts is maintained between the two cylinders 8.92 A.
Cylinder length = 0.450 m
Radii a = 1.70 cm
Radii b =2.70 cm
resistivity = 33.0 m
a) To estimate the resistance between the two cylinders, the resistance of a cylindrical conductor formula is used:
R = (ρL) / A
A = π(b^2 - a^2)
Substituting the above values in A:
A = [tex]π(2.7^2 - 1.7^2) × 10^-4 m^2[/tex]
Now we can calculate the resistance:
R = (ρL) / A
R = [tex](33.0 × 0.450) / (π(2.7^2 - 1.7^2) × 10^-4)[/tex]
R = 2.13 Ohm
b) To find the current between the two cylinders, we can use Ohm's Law.
I = V / R
Substituting the given values, we get:
I = 19.0 / 2.13
I = 8.92 A
Therefore, we can conclude that the current between the two cylinders is approximately 8.92 A.
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A light beam hits the interface between air and an unknown material at an angle of 43 degree relative to the normal The reflected ray and the refracted ray make an angle of 108 degree with respect to each other. What is the index of refraction of the material?
Answers
The index of refraction of the unknown material is approximately 1.486.
To find the index of refraction of the unknown material, we can use Snell's Law and the given information about the angle of incidence, the angle between the reflected and refracted rays, and refraction.
Determine the angle of refraction,
The angle between the reflected ray and refracted ray is 108 degrees. Since the angle between the reflected ray and the normal is equal to the angle of incidence (43 degrees), we can calculate the angle of refraction (r) using:
Angle of refraction (r) = 180 - (108 + 43)
r = 180 - 151
r = 29 degrees
Apply Snell's Law,
Snell's Law states that n1 * sin(i) = n2 * sin(r), where n1 and n2 are the indices of refraction of the two materials (air and the unknown material), i is the angle of incidence, and r is the angle of refraction.
Solve for the index of refraction of the unknown material,
In our case, n1 is the index of refraction of air, which is approximately 1. The angle of incidence (i) is 43 degrees, and the angle of refraction (r) is 29 degrees. Therefore, we can write the equation as:
1 * sin(43) = n2 * sin(29)
Calculate n2,
To find the index of refraction of the unknown material (n2), divide both sides of the equation by sin(29):
n2 = sin(43) / sin(29)
Find the value of n2,
Using a calculator, we get:
n2 ≈ 1.486
So, the index of refraction of the unknown material is approximately 1.486.
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you park your car in the sun with the windows rolled up, and the interior temperature rises from 35 ∘c at 100 kpa to 49 ∘c . the interior volume of your car is roughly 1.5 m × 2.0 m × 1.0 m.
Answers
The mass of air in the car is 3.39 kg and the energy delivered from the Sun to the interior is 35,915..2
(a) To calculate the mass of air in the car, we need to find the volume of the car's interior, which is given as 1.5 m × 2.0 m × 1.0 m = 3 m³. We then multiply the volume by the density of air at 35 ∘C, which is given as 1.13 kg/m³. So, the mass of air in the car is:
Mass = Volume x Density = 3 m³ x 1.13 kg/m³ = 3.39 kg
Therefore, the mass of air in the car is 3.39 kg.
(b) To calculate the energy delivered from the sun to the interior, we can use the formula:
Energy = mass x specific heat capacity x change in temperature
Here, the mass of air in the car is 3.39 kg, and the specific heat capacity of air is given as 720J/K kg. The change in temperature is:
ΔT = 49 ∘C - 35 ∘C = 14 ∘C
So, the energy delivered from the sun to the interior is:
Energy = 3.39 kg x 720J/K kg x 14 K = 34,915.2 J
Therefore, the energy delivered from the sun to the interior is 34,915.2 J.
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COMPLETE QUESTION:
You park your car in the sun with the windows rolled up, and the interior temperature rises from 35°C at 100 kPa to 48°C. The interior volume of your car is roughly
1.5m×2.0m×1.0m
(a) What is the mass of the air in the car, assuming a mass density of 1.13kg/m for air at
35°C?
(b) How much energy was delivered from the Sun to the interior to raise the temperature as indicated if all the energy went into the air? Use 720J/K ⋅ kg for the specific heat capacity of air.
